Polarization and satellites positions

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Old 09-07-2009   #1
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Question Polarization and satellites positions

Hi, ppl could anybody can explain to me technically , The relation between polarization and satellites positions ( Regarding to the Rule that the polarization depends on the difference between the geographical longitude position of the receiving site and the orbital position of the satellite . ) .

Any thoughts you would have be greatly appriciated .

Best Regards

A.M.AL-Madhi

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Old 13-07-2009   #2
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Originally Posted by al_madhi View Post
the Rule that the polarization depends on the difference between the geographical longitude position of the receiving site and the orbital position of the satellite . ) .
It depends on the latitude too. For example, if you are at the equator there is no skew change whatsoever.
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Old 13-07-2009   #3
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Originally Posted by al_madhi View Post
Hi, ppl could anybody can explain to me technically , The relation between polarization and satellites positions ( Regarding to the Rule that the polarization depends on the difference between the geographical longitude position of the receiving site and the orbital position of the satellite . ) .

Any thoughts you would have be greatly appriciated .

Best Regards

A.M.AL-Madhi
When aligning an antenna to a satellite, there are three (3) very important rules that need to be looked at in order to properly receive the signal.
• Elevation - Angle between the Earth and the satellite above the horizon. This is also referred to as the up or down movement of the satellite Dish.

• Azimuth - Compass direction the antenna is pointed towards, relative to a magnetic north. This is also referred to as the left or right movement of the satellite Dish.

• Polarization - Correction between where the antenna is relative to the curvature of the Earth, in other words your Location, and the satellites signal beam. The satellite signal is either Horizontal or Vertical polarized, but due to the longitude of the antenna location, the Dish feed horn must be rotated to correctly match the beam's polarization. Hope this helps to answer your query.
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