slowing down a motor with a vbox

iwol

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hi to all can anyone recommend a way to slow down my motor which i use with a vbox as mine seems to move veryfast,and i hope it might also reduce the noise slightly thanks iwol
 

Snuffer

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Change the gearbox or use a big Resitor to convert the Voltage down to lowerpoint where it still works.

I prefer the first option.

p.s. what for motor is't??
 

Llew

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Some info here on vbox mods -

http://www.satellites.co.uk/satellite/dish-setup-single-sat-multi-sat-motorised-systems/48137-inside-picture-v-box-ii.html

Llew
 

iwol

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cheers guys will have a look its a superjack arm
 

Manikm909

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its funny i was going to ask this question but searched first which led me here

my Jaegar SMR128G - moves very fast and it sometimes overshoots positions only a little but enough to miss peak signal.

i'll just tie a little bag of cement to the dish.
 

jeallen01

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its funny i was going to ask this question but searched first which led me here
my Jaegar SMR128G - moves very fast and it sometimes overshoots positions only a little but enough to miss peak signal.

i'll just tie a little bag of cement to the dish.
In reality, using a snetwork of parallel-connectoed wirewound resistors in series with the motor is the best idea to drop the voltage from about 36V to, say, 30V, i.e. by about 6V -> simple Ohm's Law calculation of R = V/I where
V = 6V
I - motor current (maybe 2-3A, but I can't remember exactly)
-> R = required value of resistor in Ohms = 2-3 Ohms

But also the total resistor Wattage needs to be at least I Squared x R = 3x3x (2 or3) xat least ->18W-27W -> maybe 3x 10W resistors connected in parallel (maybe something from here) and fitted in a water-resistant enclosure.

Did something very similar when I had to drive the 24V NEC H-2-H motor (probably Jaeger anyway) of my original NEC 5000 System from the 36V o/p of the Echostar AD3000ip which replaced that Rx
 

suedschwede

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I solved it like this, 2x15 silicon diodes each 1x15 pieces in series and the other 1x15 pieces connected anti-parallel (because of the polarity reversal) reduced by 15x0.7 volts = 10.5 volts
 

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